0=-4.9x^2+13x+38

Solution for 0=-4.9x^2+13x+38 equation:

0=-4.9x^2+13x+38

We move all terms to the left:

0-(-4.9x^2+13x+38)=0

We add all the numbers together, and all the variables

-(-4.9x^2+13x+38)=0

We get rid of parentheses

4.9x^2-13x-38=0

a = 4.9; b = -13; c = -38;
Δ = b2-4ac
Δ = -132-4·4.9·(-38)
Δ = 913.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{913.8}}{2*4.9}=\frac{13-\sqrt{913.8}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{913.8}}{2*4.9}=\frac{13+\sqrt{913.8}}{9.8}
$